技术笔记PERSONAL ARCHIVE
Create a full deck of cards in Swift
记录学习 Swift 初期的一个练习,通过 Swift Playground 使用枚举、结构体、数组和排序等基础语法创建并整理一套 52 张扑克牌。
使用 Swift Playground 创建的一个程序,可以创建一套含 52 张的扑克牌,并按照花色和牌号排序。
最近开始学习 Swift 编程,学到枚举和结构体,看到最后一个 Experiment 要实现创建一套扑克,结合了一下以前写过的“双条件”排序和官方 GuidedTour,弄了下面的代码实现。
// Base card rank
enum Rank: Int {
case ace = 1
case two, three, four, five, six, seven, eight, nine, ten
case jack, queen, king
func simpleDescription() -> String {
switch self {
case .ace:
return "ace"
case .jack:
return "jack"
case .queen:
return "queen"
case .king:
return "king"
default:
return String(self.rawValue)
}
}
func equals(compare: Rank) -> Bool {
return self.rawValue == compare.rawValue
}
}
// Card suit
enum Suit {
case spades, hearts, diamonds, clubs
func simpleDescription() -> String {
switch self {
case .spades:
return "spades"
case .hearts:
return "hearts"
case .diamonds:
return "diamonds"
case .clubs:
return "clubs"
}
}
func color() -> String {
switch self {
case .hearts, .diamonds:
return "red"
case .spades, .clubs:
return "black"
}
}
}
// Poker struct with rank and suit.
struct Poker {
var rank: Rank
var suit: Suit
func description() -> String {
return "This card is a \(suit.color()) \(suit.simpleDescription()) \(rank.simpleDescription())."
}
}
var poker = [Poker]()
// Add cards
for i in 1...13 {
poker.append(Poker(rank: Rank(rawValue: i)!, suit: Suit.spades))
poker.append(Poker(rank: Rank(rawValue: i)!, suit: Suit.hearts))
poker.append(Poker(rank: Rank(rawValue: i)!, suit: Suit.diamonds))
poker.append(Poker(rank: Rank(rawValue: i)!, suit: Suit.clubs))
}
// Order by suit, then rank
poker.sort(by: {l, r -> Bool in
if l.suit.simpleDescription() < r.suit.simpleDescription() {
return false
} else if l.suit.simpleDescription().elementsEqual(r.suit.simpleDescription()) {
return l.rank.rawValue < r.rank.rawValue
} else {
return true
}
})
// Display
poker.forEach { (item) in
print(item.description())
}